1) An ideal gas occupies a volume of 0.60 m^3 at 5atm and 400K. What volume does it occupy at 4.0atm and a temp of 200K?

Question

I know how to find the volume with the m^3 and the atm but it threw me off since it gives the 4.0 atm and the temp 200K.

Answer 1

The quantity P V/T remains constant when the number of moles remains the same.

Therefore
P1 V1/T1 = P2 V2/T2
"V2" is the final volume.

V2 = V1*(P1/P2)*(T2/T1)

= 0.60 m^3 * (5/4)*(200/400)
= ___ m^3