To solve this problem, we can use the combined gas law formula:
(P1V1)/T1 = (P2V2)/T2
Where:
P1 = 1.55 atm
V1 = 15 L
T1 = 50.0°C + 273.15 (converted to Kelvin) = 323.15 K
P2 = 2.5 atm
V2 = (unknown)
T2 = 80.0°C + 273.15 (converted to Kelvin) = 353.15 K
Plugging in the values to the formula:
(1.55 * 15) / 323.15 = (2.5 * V2) / 353.15
Solving for V2:
23.25 / 323.15 = 2.5V2 / 353.15
0.071871 = 2.5V2 / 353.15
Multiplying both sides by 353.15:
25.381 = 2.5V2
Dividing by 2.5:
V2 = 10.152 L
Therefore, the volume of the gas at 80.0°C and 2.5 atm is 10.152 L.
A sample of gas occupies 15L at 50.0°C and 1 55atm . What will its volume be at 80.0°C and 2.5atm
1 answer