1. An electric charge moves through an electric field. it accelerates, gaining 100J of energy. The change in electric potential of +10V. What is the magnitude of the charge of the particle?
I did 100J/10V to get 10C.
2. If a negative charge of double the magnitude of the first charge moved between the same two points in the field, what is the change in electric potential?
I think it was the same voltage regardless. 10V
3. What is the change in electric potential energy based off of question 2?
Not sure.
Can anyone point out anything that is wrong and show how to do it?
1 answer
1 and 2 are correct. The charge times the voltage is the change in potential energy. 100 Joules for the 10 Coulombs would be 200 Joules if the charge is doubled.
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