Let's go through each question one by one:
Question 1
Alexei can still put 39 cans on the shelf before it is full, and the shelf can hold a total of 58 cans. Therefore, the equation that represents the situation is: \[ c + 39 = 58 \] To find out how many cans (\( c \)) are already on the shelf, we solve for \( c \): \[ c = 58 - 39 = 19 \] So the correct response is: c + 39 = 58 and 19
Question 2
Trey has already run 1.2 miles and needs to complete the entire race distance. Since he has completed \( \frac{1}{4} \) of the race so far, we need to find out how many total miles the race is. Since \( \frac{1}{4} \) of the race is 1.2 miles, the race distance is: \[ \text{Total distance} = 1.2 \text{ miles} \times 4 = 4.8 \text{ miles} \] To find how many more miles he needs to run to complete the race: \[ \text{Miles left} = 4.8 - 1.2 = 3.6 \text{ miles} \] So the correct response is: 3.6 miles
Question 3
Carlos wants to average 25 points over 7 games. He has scored the following points: 27, 18, 24, 32, 15, and 27. Therefore, the equation to find the score he needs in the last game (\( s \)) to achieve this average is: \[ \frac{27 + 18 + 24 + 32 + 15 + 27 + s}{7} = 25 \] Calculating the sum: \[ 27 + 18 + 24 + 32 + 15 + 27 = 143 \] Thus, the correct equation is: \[ \frac{143 + s}{7} = 25 \] So the correct response is: (27 + 18 + 24 + 32 + 15 + 27 + s)/7 = 25
Question 4
The club sells candy bars for $2 each, bought for $400, and wants to make at least $1000, meaning their earnings must cover costs plus desired profit. Therefore we want to represent the profit in the inequality: \[ 2b - 400 \geq 1000 \] Solving this: \[ 2b \geq 1400 \] \[ b \geq 700 \] Since they bought 725 bars, and 725 is greater than 700, it is a viable option to make at least $1000 profit. So the correct response is: 2b − 400 ≥ 1000, and yes, it is a viable option
Question 5
The horse trainer has a total of 42 mints and needs 5 mints per horse per training session. Therefore, the equation to show the number of horses (\( h \)) she can train is: \[ 5h = 42 \] Solving for \( h \): \[ h = \frac{42}{5} = 8.4 \] Since you cannot train a fraction of a horse, this is not a viable option. So the correct response is: 5h = 42 so h = 8.4 horses, which is not viable
To summarize:
- c + 39 = 58 and 19
- 3.6 miles
- (27 + 18 + 24 + 32 + 15 + 27 + s)/7 = 25
- 2b − 400 ≥ 1000, and yes, it is a viable option
- 5h = 42 so h = 8.4 horses, which is not viable