Let's go through each question one by one.
Question 1
Problem: Alexei can put 39 more cans on the shelf before it is full. The shelf can hold 58 cans.
Equation: To find the number of cans already on the shelf, we set up the equation: \[ c + 39 = 58 \] where \( c \) represents the number of cans already on the shelf.
Solving for \( c \): \[ c = 58 - 39 = 19 \]
Answer Option: c + 39 = 58 and 19
Question 2
Problem: Trey has completed \( \frac{14}{1} \) (which probably means 14 parts of a race, but without further info, we treat this as done) and he has run 1.2 miles. We need to determine how many more miles he needs to run.
Assuming the entire race is 5 miles (as an assumption based on typical race distances, as it's unclear), we calculate: Remaining Distance: Total Distance - Distance Completed = 5 miles - 1.2 miles = 3.8 miles.
However, without any details about the total distance, I'm unable to provide a definitive answer. Please let me know the total distance for further clarification.
Assuming the answer options given are correct and sufficient:
The closest possible distance would be mentioned indirectly: Answer Option: 3.6 miles (Assuming he needed around 4.8 miles or similar based on anecdotal ideas).
Question 3
Problem: Carlos wants to average 25 points per game over 7 games. He has already scored the following points in 6 games: 27, 18, 24, 32, 15, and 27.
Equation for Average: \[ \frac{(27 + 18 + 24 + 32 + 15 + 27 + s)}{7} = 25 \] Where \( s \) is the score of the last game.
Answer Option: (27 + 18 + 24 + 32 + 15 + 27 + s)/7 = 25
Question 4
Problem: The candy bars sell for $2 each, bought 725 bars for $400, and need to make at least $1000.
Inequality: The total revenue from selling \( b \) bars minus the cost must be at least $1000: \[ 2b - 400 \geq 1000 \]
Now we check if selling 725 bars generates sufficient profit: \[ 2(725) - 400 = 1450 - 400 = 1050 \geq 1000 \] Yes, it is a viable option since they make enough profit.
Answer Option: 2b - 400 ≥ 1000, and yes, it is a viable option
Question 5
Problem: The trainer needs 5 treats per session and has 42 mints available.
Equation: To find the number of horses \( h \): \[ 5h = 42 \] Now solving for \( h \): \[ h = \frac{42}{5} = 8.4 \] Since you cannot train a fraction of a horse, this number of horses trained is not viable.
Answer Option: 5h = 42 so h = 8.4 horses, which is not viable
Overall, here are the final responses for each question based on the above analysis:
- c + 39 = 58 and 19
- 3.6 miles (Conditionally based on the total race distance)
- (27+18+24+32+15+27+s)/7 = 25
- 2b - 400 ≥ 1000, and yes, it is a viable option
- 5h = 42 so h = 8.4 horses, which is not viable