Question

1. A line through (-5,-4) and (2,4) is perpendicular to a line through (-6,y) and (2,3). Find y.

2. The points (x,-3), (-4,1) and (2,3) lie on the same line. Find the value of x.

3. Given two points A(3,1) and B(-12,-1), determine a third point P(x,y) such that the slopes of AP and BP are -2/3 and 2/3 respectively.

Answer 1

1. A line through (-5,-4) and (2,4) is perpendicular to a line through (-6,y) and (2,3). Find y.
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I will not do them for you. Here is how to start. They are really all the same.
What is the slope of that first line?
m = (Y2-Y1) / (X2-X1) = (4 - -4) / (2 - -5) = 8/7
so what is the slope of a line perpendicular to that?
m' = -1/m = -7/8
so
-7/8 = (3-y) / (2+6)
8 (3-y) = -7(8)
3 - y = -7

Answer 2

Thank you very much! Now I already answered those problems! Thank you