The sum of the heats gained is zero.
Heat gained by water+heatgainebysteel+ heat gained by iron pot = 0
1.35kg*cwater*(25-20)+.40(csteel)(25-Ti)+.30*ciron(25-20)=0
solve for Ti if the steel horseshoe.
1). A hot iron horseshoe (mass=.40kg), just forged, is dropped into 1.35L of water in a .30kg iron pot initially at 20.0 degrees Celsius. If the final equilibrium temperature is 25.0 degrees Celsius, estimate the initial temperature of the hot horseshoe.
2). A cube of ice is taken from the freezer at -8.5 degrees Celsius and placed in a 95kg aluminum calorimeter filled with 310 g of water at room temperature of 20.0 degrees Celsius. The final situation, is observed to be all water at 17.0 degrees Celsius. What was the mass of the ice cube?
1 answer