1. A 3kg box is released from the top of a 20° inclined plane. If the length of the inclined plane is 10m long, and a frictional force of 10N opposes the motion of the ball, Determine the speed of the ball when the ball reaches the bottom of the plane.

2 answers

effective weight of box = 3*9.81 cos20° = 27.655
net downward acceleration = 17.655
v = √(2as) = √(2*17.655*10) = 18.79 m/s
Help me to find the speed of the ball reaches the bottom of the plane