1.578 g of an unknown hydrocarbon (110.7 g/mol) burns in bomb calorimeter in excess oxygen. The heat capacity of the calorimeter,Cv, = 5.709 kJ/ºC and ΔT =7.995 ºC. Find ΔE for this hydrocarbon in kJ/mol.

Answer 1

dE = Ccal*dT and that is kJ (if you use Ccal in kJ) for 1.578/110.7 mol xample. Convert that to kJ/1 mol.