1.50 g NaHCO3 in 17.1 g H2O. So in 100, there is
1.50 g NaHCO3 x (100/17.1) = approx 9 but you need to do it more accurately.
% NaHCO3 = (g NaHCO3/total g)*100 = (9/109)*100 = ?
%H2O = (gH2O/total g)*100 = (100/109)*100 = ?
1.50g of NaHCO3 is dissolved in 17.1g of water. Express the solubility of NaHCO3 in grams per 100g of solvent and calculate the % composition of NaHCO3 and water.
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