since 1+2+...+k = k(k+1)/2
Your sum is
n
∑ 2/(k(k+1))
k=1
see what you can do with that.
Note that
1/(k(k+1)) = 1/k - 1/k+1
1+ 1/1+2+ 1/1+2+3....to n terms.
3 answers
sir answer this question 2n/n+1
what question? You have the sum correct.