0.250g of phthalic acid is dissolved in 40.00cm^3 of 0.100 mol dm^-3 NaOH. It requires 11.80 cubic centimeters of 0.100 mol\dm^-3 HCL fo neutralisation( to phenolphthalein) The mole ratio in which phthalic acid reacts with sodium hydroxide ihn 1:2

Question

(a) Calculate the moles of excess NaOH reacted with HCL
(b)Calculate the moles of phthalic acid used
(c) Calculate the molecular mass of phthalic acid

Answer 1

0.250 g of phthalic acid is dissolved in 40.00 cm3 of 0.100 mol dm-3 NaOH. It
requires 11.80 cm3 of 0.100 mol dm-3 HCl for neutralisation (to
phenolphthalein). The mole ratio in which phthalic acid reacts with sodium
hydroxide is 1:2.

Answer 2

What's the answers for the question?

Answer 3

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