H2A + 2NaOH ==> Na2A + 2H2O
mols NaOH = M x L = ?
mols H2A = 1/2 x mols NaOH (look at the coefficients in the balanced equation).
Then mols H2A = grams H2A/molar mass H2A. You know mols and grams, solve for molar mass.
A student completes a titration of an unknown diprotic acid. In this experiment, 0.79 g of the acid is dissolved in 250.0 mL of water. It requires 13.48 mL of 1.0 M NaOH to reach the second equivalence point. What is the molar mass of the acid?
1 answer