pi vi^1.4 = pf vf^1.4 where i is initial and f is final
so
vf^1.4 = pi/pf vi^1.4 = 140/700 (.2)^1.4 = 0.2 * 0.105
vf^1.4 = 0.0210
1.4 log vf = log 0.0210 = -1.678
log vf = -1.198
vf = 0.0633 m^3
0.2 m^3 of a gas has pressure of 140kPa .it is compressed to pressure of 700kPa according to the law PV^1.4=C. Determine the new volume of gas.
1 answer