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yuriy
Questions (1)
find the two numbers that are twice as far from 15 as they are from 24
3 answers
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Answers (3)
a) |a|= 30 cm 1/2 period = 10 period = 20 k= 360/ period = 360/20 = 18 p = 2 a = -30 (as a reflected cosine) therefore, d(t)= -30 cos{18(t-2)} b) Reduce sway = reduce of amplitude |a|= 100% - 70% = 30% |a| = 30 (.3) = 9 cos{ 18(t-2)}
15 + 2x = 24 - x 3x = 24 - 15 3x = 9 x = 3 2nd # 15 + 6 = 21
24 + x =15 + 2x x = 9 1st # 24 + 9 = 33
