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An aqueous solution is 40.0% by mass hydrochloric acid, HCl, and has a density of 1.20 g/mL.
The molality of hydrochloric acid in
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0.471 m means 0.471 mols Co(NO3)2 in 1 kg solvent. How many g Co(NO3)2 is 0.471 mols? That's g = mols x molar mass = ? = approx 86 grams Co(NO3)2 Total mass of the solution then is approx 86 + 1000 = approx 1086g total. % = (g solute/total grams
