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victor_hery
Questions (2)
solve, tan 10 degrees + tan 70 degrees - tan 50 degrees = ....
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how to prove ; tan 10 degrees + tan 70 degrees - tan 50 degrees = sqrt 3
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what do you ask? may be not complete ....
y^2 - 4y^8 = y^2 - (2y^4)^2 = (y + 2y^4)(y - 2y^4) formulas a^2 - b^2 = (a + b)(a - b)
Sin (180 - A) = sin A. (angle in degrees) sin 120 = sin (180 - 60) = sin 60 Cos (180 - A) = - cos A cos 150 = cos (180 - 30) = - cos 30 tan (360 - A) = - tan A, tan 280 = tan (360 - 80) = - tan 80
(tan5 + tan25)/(1 - tan5tan25)= tan (5+25) = tan 30 degrees = (sqrt 3)/3