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vace
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i think its this: Volume of final solution = (100.0 + 113.0) mL = 213.0 mL [CH₃COOH] = (1.151 M) × (100.0/213.0) = 0.5404 M [CH₃COO⁻] = (1.270 M) × (113.0/213.0) = 0.6738 M Henderson-Hasselbalch equation: pH = pKa + log([CH₃COO⁻]/[CH₃COOH])
