ur class fella

Hi, Can any1 help with theses questions. I need to solve these because there will be similar questions on the midterm for me, coming week. Btw I have tried few. 1. How many milliliters of a 15.0%, by mass solution of KOH (Aq) ( d= 1.14g/mL ) are required...

lolz, you must a chma11 student at utsc. you are doing a great job for other 799 kids taking this course. keep it up. lol me stuck on the same question.

some 1 help it is due 9 am tomorrow. for the chart the solubility curves at kno3 in any general chemistry text book.

holy, we CHMA11 kids are all over the internet. trying to find how to work out the pre-labs and mastering chemistry homework.

yeah it should be around or less den 2. i mean the i should be = 2 because it breaks into to ions for KCL and i am getting 1.6. pretty close eh.

But these questions were never taught in the class and they are appearing on the mid-term.

ok, here is the thing. I have tried other questions and got the right answer :P But for question # 2 I convert the ph to pOH and den find the OH- den I find the # of moles from 6.8% ammonia and den I use the Kb value of ammonia to find the OH- in the 6.8%...

Ok here is my solution to it but i am constantly told that it is wrong. d=0.97g/mL Mass %= 6.8% 1000mL= 1L d=m/v m=d X v m= 0.97g/mL X 1000mL m=970g mNH3 = 970g X 0.068=65.96g of NH3 MM of NH3 = 14g/mol + 3 X 1g/mol=17g/mol nNH3 = 65.96g/17g/mol n=3.88mol...

and forgot to mention, I need a volume of 625mL of pH of 11.65....differnt from the original question posted....

oh my God ...how did you guys do at the mid-term.. lol i beat the class average by 15% which is great, I guess