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tiklam

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First Calculate the KE of the sledge hammer. 2: Calculate the speed of the Merry-go-round (MGR) from m1.v1+m2.v2=m1.v1'+m2.v2'. Note: v2 and v1' are zero 3: Calculate angular KE of the MGR 4: Lost energy =1-3 So if you can't solve this then you should go
b) Find Mu_s first Mu_s= (m_p/3 + m_l/2) *cotan (theta)/(m_p+m_l) a) Force = Mu_s*g(m_p+m_l)
a: mg (90*10=900) b: No sure yet c: Conservation of energy gives: m*g*R(1-cos(theta))=0.5*m*v^2 at fly off there is no force on the dome. so m*g*R*cos(theta)=(mv^2)/R Use these equations to eliminate v^2 you will get Cos-1(2/3) Theta= 48.10 Degrees
use the motion equations. s=ut+0.5at^2 where s=distance traveled by center of mass Rcm u=0= initial velocity a= acceleration comes from force calculation i.e. force down=mg force up=F Therefore acceleration=(F-mg)/m Substitute in the equation at the top

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