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Answers (1)
pOH= 14- 12.4 = 1.6 [OH-] = 10^-1.6 = .025 M OH- mols of OH- = .025 M * .2L =.005 mols .005 mols OH- * (2 mols e-/ 2mols )OH-) * (96500 C / 1 mole e-) = 484.8 C amps = 484.8 C / (10 min*60) = .81 A