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soma sekharam
Answers (1)
initial speed u=7.2m/s final speed v=0 distance traveled s=3.8m coefficient of kinetic friction muK =? We know that v^2-U^2=2as 0^2-U^2=2*(-muk^g)s muk=(U^2)/(2*g*s) = (7.2*7.2)/(2*9.8*3.8) =0.696(no units) = 0.70 (n0 units and two significant figures)