Ask a New Question
Search
Questions and answers by
shein
Answers (1)
With no girls C(10,4) = 210 ways With one girl 12 C(10,3) = 12*120 = 1440 ways With two girls first combinations of 12 girls taken 2 at a time = 12!/[10!*2!) = 12*11/2 = 66 (my table of binomial coefficients only goes to n = 10) time combinations of ten
