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saiko
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as the summation 50+65+70=185 and some students chose none, so it is greater than 150 total students. so the sets can't be disjoint. there are students who took more than 1 elective.
48
1> even factors of 4*5 =20 so the factors are 1, 2 ,4 ,5 ,10 ,20 among them 2,4,10,20 are even. 3> here 4 is the minimum no of +ve factors. n will have the factors, =1*n =p*q including 1 and n, n have minimum 4 factors. it could be more. ***for Q2 I have
where are the cubes??
multiple of 3 are 3,6 so the probability is 2/8
so you have, (n-2)+(n-1)+n+(n+1)+(n+2)=2005 5n=2005 n=401 nos are, 399,400,401,402,403
(1-1/3)*1*V=(1-3/4)*p*V p=8/3=2.6667 gm/cc
add them!! adding it comes 11 hrs subtract 11 from 12
remainder is=f(-2) f(-2)=2(-2)^6-8(-2)^4+(-2)^2-5 =-3 so (x+2) is not a factor of f(x)
P((x-72)/9)=90% (x-72)/9=1.28 [normal distribution table] x=83.52 83.52 at least for getting A P((x-72)/81)=10% (x-72)/81=-1.28 [normal distribution table] x=60.48 60.48 maximum for getting D for B, score is between 72 and 83.52 for C, score is between
for 2 answer is 1 is ok
(47-32)*5/9 =8.333333333333 degree centigrade
V=pi*r^3 dV/dt=3*pi*(r^2)*(dr/dt) dV/dt=.1 r=2 pi=3.14 dr/dt=?
total arrangement=(6+3-1)!=8! with 2 girls sit beside, arrangement possible=3C2*(6+2-1)!=3*7! probability 2 girls always sit beside=3/8 answer=1-3/8=5/8
2.5 m from where? right end or left end?
the normal force on the block, mg-p*sin_theta along the motion, p*cos_theta=u*(mg-p*sin_theta) theta=30 u=.6 m=300 kg p*(.866+.5*.6)=.6*300*9.8 p=1512 N if p is individual of two force then, p=1512/2=756 N
d>=51+12 d>63 or d=63
yes this is true.
I am solving the first one.....second one you can try yourself. so 9x^4+4=13x^2 this can be written, x^2*(9x^2-13)=-4 as x^2 is always +ve so to be -ve, (9x^2-13)
mean is calculated as the average value. summation of all values divided by number of values is mean. and median is the value present in the middle of a sequence of numbers.
correctio:: ....an easy access to search for.....
so kevin travels 50*60 meter/ hour that is=3 km/hr
he spend (1/4+1/2)=3/4 of his total money. so has remaining money=(1-3/4)=1/4 of total money. he had total money=$58*4=$432
taking the ininverse, (-x^2 + 2)/2x=-x/2+1/x so the answer is =1/((1/x)-(x/2))
1-cos(power 2)x= sin(power 2)x sin(power 2)x/sin(x)=sin(x)
at time 0 the position is (0,0) at any time t, the distance wold be, =sqrt((t-sint)^2+(1-cost)^2) =sqrt((t-sint)^2+(1-cost)^2) =sqrt(t^2+2-2(cost+tsint)) now integrate this from 0 to 2pi to get the answer. wolframalpha refer to the site to get ur
2cos^2(x)=2-2sin^2(x) substituting, 5-2+2sin^2(x)-7sin(x) = 0 it comes as 2p^2-7p+2=0 where p=sinx solving p=13/4,1/4 as sin(x)
well you can understand it like, for one qusetion getting right, the probability is=.5 as there are only two options true and false. for two qusetion getting right, the probability is=.5*.5 for three qusetion getting right, the probability is=.5*.5*.5
1> Phloem Transportation of food and nutrients such as sugar and amino acids from leaves to storage organs and growing parts of plant. This movement of substances is called translocation. Xylem Water and mineral transport from roots to aerial parts of the
the area of the path that is running along the breath is= 450*5=2250 m^2 the area of the path that is running along the length is= 750*5=3750 m^2 but as the two roads cross each other in the middle if we just sum the two areas it would over-estimate the
