saiko
This page lists questions and answers that were posted by visitors named saiko.
Questions
The following questions were asked by visitors named saiko.
Answers
The following answers were posted by visitors named saiko.
the area of the path that is running along the breath is= 450*5=2250 m^2 the area of the path that is running along the length is= 750*5=3750 m^2 but as the two roads cross each other in the middle if we just sum the two areas it would over-estimate the c...
12 years ago
1> Phloem Transportation of food and nutrients such as sugar and amino acids from leaves to storage organs and growing parts of plant. This movement of substances is called translocation. Xylem Water and mineral transport from roots to aerial parts of the...
12 years ago
well you can understand it like, for one qusetion getting right, the probability is=.5 as there are only two options true and false. for two qusetion getting right, the probability is=.5*.5 for three qusetion getting right, the probability is=.5*.5*.5 ......
12 years ago
2cos^2(x)=2-2sin^2(x) substituting, 5-2+2sin^2(x)-7sin(x) = 0 it comes as 2p^2-7p+2=0 where p=sinx solving p=13/4,1/4 as sin(x)<=1 so sin(x)=1/4 a=1 b=4 a+b=5
12 years ago
at time 0 the position is (0,0) at any time t, the distance wold be, =sqrt((t-sint)^2+(1-cost)^2) =sqrt((t-sint)^2+(1-cost)^2) =sqrt(t^2+2-2(cost+tsint)) now integrate this from 0 to 2pi to get the answer. wolframalpha refer to the site to get ur integrat...
12 years ago
1-cos(power 2)x= sin(power 2)x sin(power 2)x/sin(x)=sin(x)
12 years ago
taking the ininverse, (-x^2 + 2)/2x=-x/2+1/x so the answer is =1/((1/x)-(x/2))
12 years ago
he spend (1/4+1/2)=3/4 of his total money. so has remaining money=(1-3/4)=1/4 of total money. he had total money=$58*4=$432
12 years ago
so kevin travels 50*60 meter/ hour that is=3 km/hr
12 years ago
correctio:: ....an easy access to search for.....
12 years ago
mean is calculated as the average value. summation of all values divided by number of values is mean. and median is the value present in the middle of a sequence of numbers.
12 years ago
I am solving the first one.....second one you can try yourself. so 9x^4+4=13x^2 this can be written, x^2*(9x^2-13)=-4 as x^2 is always +ve so to be -ve, (9x^2-13)<0 we see that -(sqrt(13)/3)<x<(sqrt(13)/3) it comes as -1.2<x<1.2 next we will see if there...
12 years ago
yes this is true.
12 years ago
d>=51+12 d>63 or d=63
12 years ago
the normal force on the block, mg-p*sin_theta along the motion, p*cos_theta=u*(mg-p*sin_theta) theta=30 u=.6 m=300 kg p*(.866+.5*.6)=.6*300*9.8 p=1512 N if p is individual of two force then, p=1512/2=756 N
12 years ago
2.5 m from where? right end or left end?
12 years ago
total arrangement=(6+3-1)!=8! with 2 girls sit beside, arrangement possible=3C2*(6+2-1)!=3*7! probability 2 girls always sit beside=3/8 answer=1-3/8=5/8
12 years ago
V=pi*r^3 dV/dt=3*pi*(r^2)*(dr/dt) dV/dt=.1 r=2 pi=3.14 dr/dt=?
12 years ago
(47-32)*5/9 =8.333333333333 degree centigrade
12 years ago
for 2 answer is <d> 1 is ok
12 years ago
P((x-72)/9)=90% (x-72)/9=1.28 [normal distribution table] x=83.52 83.52 at least for getting A P((x-72)/81)=10% (x-72)/81=-1.28 [normal distribution table] x=60.48 60.48 maximum for getting D for B, score is between 72 and 83.52 for C, score is between 60...
12 years ago
remainder is=f(-2) f(-2)=2(-2)^6-8(-2)^4+(-2)^2-5 =-3 so (x+2) is not a factor of f(x)
12 years ago
add them!! adding it comes 11 hrs subtract 11 from 12
12 years ago
(1-1/3)*1*V=(1-3/4)*p*V p=8/3=2.6667 gm/cc
12 years ago
so you have, (n-2)+(n-1)+n+(n+1)+(n+2)=2005 5n=2005 n=401 nos are, 399,400,401,402,403
12 years ago
multiple of 3 are 3,6 so the probability is 2/8
12 years ago
where are the cubes??
12 years ago
1> even factors of 4*5 =20 so the factors are 1, 2 ,4 ,5 ,10 ,20 among them 2,4,10,20 are even. 3> here 4 is the minimum no of +ve factors. n will have the factors, =1*n =p*q including 1 and n, n have minimum 4 factors. it could be more. ***for Q2 I have...
12 years ago
48
12 years ago
as the summation 50+65+70=185 and some students chose none, so it is greater than 150 total students. so the sets can't be disjoint. there are students who took more than 1 elective.
12 years ago