roseanne

Calculate the molar solubility of MX2, if the Ksp=3.3x10^-8 i already asked this but im confused about one of the steps. Ksp = (x)(2x)^2 = 4x^3 = 3.3X10^-8 x = solubility = 0.00202M. but i don't understand do i substitute the x in 4x^3 3.3X10^-8 and then...

given the points A (-4 ,3) B (12 ,11) and C (4,7) .point c divides AB into what ratio?

that helped a lot, thanks!

i tried solving it on my own but im confused by the steps and when i calculate i don't end up with 0.00202. please help!

thanks! it looks like i was calculating the cube and not the cube root!