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roro
Questions (10)
what is the method to prepartion CO from these equation in the lab
CaCo3 + 2HCl → CaCl2+H2O+ CO2 (g) Or CaCo3 ----(Heat 500 to
2 answers
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how to prepare CO from this equation in the lab CaCo3 + 2HCl → CaCl2+H2O+ CO2 (g)
Or CaCo3 ----(Heat 500 to 600 C0→ Cao +Co2
3 answers
680 views
Damion wants to be a construction worker right out of high school and then work up to be a site foreman. He eventually wants to
1 answer
651 views
A 0.43 kg object connected to a light spring with a spring constant of 21.4 N/m oscillates on a frictionless horizontal surface.
0 answers
521 views
A 0.30 kg mass is attached to a spring with a spring constant 170 N/m so that the mass is allowed to move on a horizontal
0 answers
664 views
A object-spring system undergoes simple harmonic motion with an amplitude of A. Does the total energy change if the mass is
1 answer
1,219 views
Starting at = 0 , a horizontal net force 0.280 (-0.440 is applied to a box that has an initial momentum -2.90 4.10 .
1 answer
581 views
Two ice skaters, Daniel (mass 70.0 ) and Rebecca (mass 45.0 ), are practicing. Daniel stops to tie his shoelace and, while at
1 answer
1,721 views
Consider the following reaction
Al(OH)3 + 3HCL ____>ALCL3 How many milliltres of 0.8 M HCL will react with 2g of AL(OH)3 ??
2 answers
950 views
Mrs. Carroll and her sister want to keep their taxes low and keep Ms. Howard's liability to the amount of her original
1 answer
431 views
Answers (8)
the question is how to work in the lab by using these equation to get CO , i have CaCo3 powder and i do not have any idea to prepare CO
1.115 11.5%
answer plz
He analizado antes de poder ver la solución para ver los pasos Gracias roro
2*12s + 2*20c + (2s + 10c) 24s + 40c + 2s + 10c 26s + 12c
when you used the calculator to find (-8)/(2)(2) you did not consider the order of operations you must multiply 2 by 2 before you divide -8 by the answer, otherwise your method is correct
y= x^2 -x - 9 y=(x^2 -x + 0.5^2 - 0.5^2) -9 ; we get 0.5 by dividing 1 by 2) y=(x^2 -x + 0.25) - 0.25 -9 y=(x-0.5)^2 - 9.25
x*y = 24 y = x - 5 so the equation becomes: x*(x - 5) = 24 expand: x^2 - 5x - 24 - 0 Factor by sum and product method: (x - 8)(x + 3) = 0 so x = 8 or x = -3 since the integers are positive, the solution is x = 8, and y = x - 5, so y = 8 - 5, y = 3 the two
