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Questions and answers by
ritwik durga
Answers (1)
ph of naio3 is 4 as concentration is 0.0001M and (h+) conacentration is ten to the power of minus four. by writings balanced equations we get, enot=0 e cell=-0.0591*log10^4 e cell=-0.0591*4 :e cell=0.06*4=0.24 thank you
