Ask a New Question
Search
Questions and answers by
rakul kapoor
Answers (1)
If initial velocity be u and the acceleration be a then the distance in first 5s will be S 5 =u(5)+ 2 a(5) 2 =40m........(1) and the distance in first 10s will be S 10 =u(10)+ 2 a(10) 2 so the distance between time t=5s to t=10 will be S 5
