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raheel khan
Questions (1)
A particle p moves in a straight line with a velocity v m/sec that is given by v=4t^2-1 where t is the time after passing
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Answers (1)
Taking differential with respect to x on both sides d/dx y =d/dx(1-cos^2x) dy/dx = d/dx1 -d/dx(cosx)^2 dy/dx =0 - 2cosx *d/dx cosx. dy/dx= -2cosx*(-sinx) d/dx x dy/dx=2sinxcosx *1 dy/dx=sin2x [d/dx (x) =1] by first principle
