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prasis
Answers (1)
k tan B = tan A k sin B / cos B = sin A / cos A k sin B cos A = sin A cos b k (2 sin B cos A) = 2 sin A cos B k (sin(A+B) - sin (A-B)) = sin (A-B) + sin(A+B) k sin (A+B) - sin (A+B) = sin (A-B) + k sin (A-B) (k-1) sin (A+B) = (k+1) sin (A-B)
