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Assess with explanation the bioavailability by oral route of the following drugs with the specified properties.Also suggest ways
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A mixture containing 19.8 moles of H2 and 7.2 mole of I2 was allowed to reach equilibrium in a 5 L closed vessel at ToC
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forums.studentdoctor.n et/thr eads/equilibrium-calculation.1113998/Please to delete space
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May be the problem is unclear Anyway, Thank you for your help sir!
3bi Kc2 = [HCl(g)]^2/Kc(1) [H2(g)] [Cl2(g)] 3bii Combine two reaction together, I have H2 + Cl2 ⇌ 2HCl Kc=[HCl]^2/[H2][Cl2] = Kc1 X Kc2 = 94.2647 Let y be the change of no. of mole of H2(g) H2 + Cl2 ⇌ 2HCl Final no. of mol (0.13287-y) 0.56338 2y Is it
Oh...yes.I was careless,(HI) should be equal to 2x
Thank you for your help Yes it is past exam paper and I have a exam after tomorrow Kc1 I got 6.865,so 6.865=(2x)^2/((1.77*10^-3)-x)((2.5*10^-3)-x) 6.865=4x^2/x^2-(4.273*10^-3)+(4.433*10-6) (2.865)x^2-(0.0293)x+(3.043*10^-5)=0 Are the steps correct above?
6.865 = x^2 / ((45/253.8/100)-0.5x)((0.5/2/100)-0.5x) This equation is OK?because the mole ratio of H2 to Hi is 1:2 So [HI]=x=5.33*10-4M HI =6.813g?
A mixture containing 19.8 moles of H2 and 7.2 mole of I2 was allowed to reach equilibrium in a 5 L closed vessel at ToC according to the equation: H2 (g) + I2 (g) 2HI (g) At equilibrium, 14 moles of H2 was present. The equilibrium constant for this

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