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What is the pH of an aqueous solution of 0.10 M NaHC(3)H(2)O(4)?
Answer: 10.9 What I did: NaHC(3)H(2)O(4) + H(2)O--><-- Na +
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thank you; I was pretty sure I couldn't assume x negligible for Ka but I thought that the test for negligibility was the same as the test for % ionization.
I guess not; I thought it was, but I could be wrong. If it's not malonic what do you think it is?