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Trapezoid ABCD, top and bottom are parallel. Left is 45, bottom is 60, right is 30, top is unknown. Trapezoid EFGH is similar to ABCD, top and bottom are parallel. Top is 10, other sides are unknown. Area of ABCD is 9 times larger than EFGH. What is the p...

Trapezoid ABCD, top AD and bottom BC are parallel. AD is the smaller of the two parallel lines. Left AB is 45, bottom BC is 60, right CD is 30, top AD is unknown. Trapezoid EFGH is similar to ABCD, top EH and bottom FG are parallel. EH is the smaller of t...

I don't see a problem but I will rewrite the structure. Make two rectangles attached together. Call the first rectangle ABHG (AG top, BH bottom). Call the second rectangle GHCD (HC top, GD bottom). Draw a horizontal line from line AB to line GH and name t...

20 percent is actually 20/100 or .2 87/8 is actually 10.875 The result is .2 x 10.875 or using fractions (20 x 87) / (100 x 8) = 1740 / 800 = 2 140/800 = 2 7/40 or 87/40

I am still lost. How come the areas of similar figures (trapezoids) are proportional to the squeare of their corresponding perimeters.

A word is two bytes. A byte has 8 bits.

Does this work for all trapezoids ? Is this true for all similar enclosed figures ? Can you help me with my other question posted minutes later than this one ?

There is no difference between 1-2 and 2-1 if you disregard the + or - in the final answer. Sometimes when I do calculations on the calculator and I forget which number is the larger, I will end up with a negative answer. I just remember that the answer s...

look them up using goog.le

Simple. 250 x (40/100) x (46/100) = 250 x .4 x .46 = 46 applicants will be selected.

I don't see a problem but I will rewrite the structure. Make two rectangles attached together. Call the first rectangle ABHG (AG top, BH bottom). Call the second rectangle GHCD (HC top, GD bottom). Draw a horizontal line from line AB to line GH and name t...

I reposted a better structure at 1:58 thank you for your help so far.

I looked at it another way. I used rectangle FEBH; area = 9 x EF. I used rectangle AEFG; area = 4 x EF. Ratio of area FEBH to AEFG = 2.25 The square root of area is ratio of the perimeters = 1.5 Perimeter of AEFG = 2 x 9 + 2 x EF Perimeter of FEBH = 2 x 4...

( (5 x 5) x 2 ) + 5 = (25 x 2) + 5 = 55.

Thank you for all your help.