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olav
Questions (7)
I don't see a problem but I will rewrite the structure.
Make two rectangles attached together. Call the first rectangle ABHG (AG
5 answers
551 views
There is one large rectangle ABCD, top line is AD and bottom is BC.
A vertical line is drawn from the top to bottom called GH
4 answers
558 views
There is one large rectangle ABCD, top line is AD and bottom is BC.
A vertical line is drawn from the top to bottom called GH
0 answers
803 views
Trapezoid ABCD, top AD and bottom BC are parallel. AD is the smaller of the two parallel lines. Left AB is 45, bottom BC is 60,
4 answers
780 views
There is on large rectangle ABCD, top line is AD and bottom is BC.
A line is drawn from the top to bottom called GH. A line is
0 answers
635 views
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4cm | (1) | | |_____| | | | | 9cm | (2) | (3) | | | | ------------------ Rectangle 1 & 2 & 3 are similar. What
0 answers
289 views
Trapezoid ABCD, top and bottom are parallel. Left is 45, bottom is 60, right is 30, top is unknown.
Trapezoid EFGH is similar to
1 answer
879 views
Answers (12)
Thank you for all your help.
( (5 x 5) x 2 ) + 5 = (25 x 2) + 5 = 55.
I looked at it another way. I used rectangle FEBH; area = 9 x EF. I used rectangle AEFG; area = 4 x EF. Ratio of area FEBH to AEFG = 2.25 The square root of area is ratio of the perimeters = 1.5 Perimeter of AEFG = 2 x 9 + 2 x EF Perimeter of FEBH = 2 x 4
I reposted a better structure at 1:58 thank you for your help so far.
I don't see a problem but I will rewrite the structure. Make two rectangles attached together. Call the first rectangle ABHG (AG top, BH bottom). Call the second rectangle GHCD (HC top, GD bottom). Draw a horizontal line from line AB to line GH and name
Simple. 250 x (40/100) x (46/100) = 250 x .4 x .46 = 46 applicants will be selected.
look them up using goog.le
There is no difference between 1-2 and 2-1 if you disregard the + or - in the final answer. Sometimes when I do calculations on the calculator and I forget which number is the larger, I will end up with a negative answer. I just remember that the answer
Does this work for all trapezoids ? Is this true for all similar enclosed figures ? Can you help me with my other question posted minutes later than this one ?
A word is two bytes. A byte has 8 bits.
I am still lost. How come the areas of similar figures (trapezoids) are proportional to the squeare of their corresponding perimeters.
20 percent is actually 20/100 or .2 87/8 is actually 10.875 The result is .2 x 10.875 or using fractions (20 x 87) / (100 x 8) = 1740 / 800 = 2 140/800 = 2 7/40 or 87/40
