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narlin
Answers (1)
let the final total vol = X .054L * [H]init / X liters = [H]final [H]init = 10^-4.14 mol/L [H]fin = 10^-5 mol/L by algebra, X=.3912 Liters final vol. 391.2 mL - 54 mL = 337.2 mL to add. This may be what you are looking for, but it glosses over a lot of
