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For n>= 2, let Xn be a random variable such that P(Xn = 1/n) = 1 – 1/n^2 and P(Xn = n) = 1/n^21> If Xn converges in
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Convergence in probability and varianceFor n>= 2, let Xn be a random variable such that P(Xn = 1/n) = 1 – 1/n^2 and P(Xn = n)
1. 1 answer
2. 119 views