n.e
This page lists questions and answers that were posted by visitors named n.e.
Questions
The following questions were asked by visitors named n.e.
Answers
The following answers were posted by visitors named n.e.
The person who responded is correct with their method except Faraday's constant is 96485.33. (2.303RT*ΔpH)/nF R= 8.314 T= 25 + 273.15 = 298.15 K T= 37 + 273.15 =310.15 K n= 1 F= 96485.33 For 25 degrees: (2.303*8.314*298.15*2.49)/(1*96485.33) = 0.147 V 0.1...
8 years ago
Oops, 0.147 V * 1000 = 147 mV
8 years ago