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mohameed
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assuming a peak flow velocity of 3 m/s determine culvert diameter if peak flow rate will 9790 cubic metres per second
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a1=5.5*2.5 =13.25 cm2 a2=5.3*8 =42.4cm2 a3=2.5*8/2 =10 then times by 2 cause to right triangles =20cm2 a4=8.38*5.3 =44.42 at=13.25+42.4+44.42+20 =120.11cm2