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melbell
Questions (5)
The concentration of a certain sodium hydroxide solution was determined by using the solution to titrate a sample of potassium
3 answers
3,894 views
A student mixes four reagents together, thinking that the solutions will neutralize each other. The solutions mixed together are
3 answers
2,326 views
In chemistry, we did a lab in which we had a certain mass of copper, performed multiple experiments on the copper, and at the
2 answers
2,427 views
What volume (mL) of 0.2650 N H3PO4 is required to neutralize:
a) 35.25 mL of 0.2300 M KOH b) 19.14 mL of 0.2300 M NH4OH
6 answers
724 views
If in Part B.2, the burning of the magnesium is uncontrolled (burns brightly), how will this procedural error affect the
2 answers
978 views
Answers (10)
You've gotten the moles of CO2 and H20, but now you must find the only the moles of Carbon and Hydrogen. Originally, the compound that was combusted only contained C and H. Therefore, all the C in the compound went into CO2 and all the H went into H2O. To
The only removable one is a point discontinuity, in which a single point on the graph is missing. The other two discontinuities, jump and infinite, are nonremovable. A jump discontinuity is when the graph "jumps" in y-value and does not connect, while an
Multiply 23 grams of zirconium by the molar mass of zirconium, and then by Avogadro's number (6.022x10^23) to get the number of atoms in 23 grams of zirconium. Then, since we had the grams of zirconium and converted it into atoms of zirconium, we are going
Thank you so much! this is a lot easier than the way I was originally trying to solve it
Thank you Dr. Bob
Great thanks! And I looked up the melting point of copper and it's 1085 degrees Celsius and it sure isn't getting that hot haha so it would make sense that 100 degrees Celsius is the maximum temperature.
Yes, thank you very much!! and for part b I ended up getting 16.61 mL. Thank you for your help
Unfortunately, that's all the information I have. The point of doing these problems on the site called "CalmWeb" is so that we can't look up the answers in the back of the book, because we only know we have the answer correct once we type it in, so sorry
Ok, I think I get it now. Thank you so much!
if the burning of magnesium is complete, is seems that that is not a procedural error. after completion the mass of magnesium should be the same and now you have increased mass of magnesium oxide because before you had none
