mathneed helps

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Questions

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The acceleration of the position function s(t) = 4t^2– 8t + 2 when t = 7. a) 7 b) 48 c) 142 d) 8
3 years ago

Answers

The following answers were posted by visitors named mathneed helps.

s(t) = 4t^2– 8t + 2 when t = 7 = 4(7)^2-8(7)+2 = 4(49)-56+2 = 196-54
3 years ago
s(t) = 4t^2– 8t + 2 when t = 7 = 4(7)^2-8(7)+2 = 4(49)-56+2 = 196-54 = 140+2 = 142
3 years ago