mathew guru

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∆PQT=65-25=40°. ∆PST=90+65=115. PT=? ST=20m PTsin40°=20sin115° PT=28.2m

Height of the flagpole Sin65°=X/28.2 X=28.2sin65°=25.6m

Distance QT Cos65°=25.6/X X=25.6/cos65°=11.9m To find distance QT Cos25°=11.9/X X=11.9/cos25°=13.1m