kyu

Suppose that X is an angle in standard position and that X' is it's reference angle. If cosX = -4/ squareroot of 17. find the exact value of cosX' is it 4/square root of 17?

Find the Cartesian form of the parametric equation. x = (2a)(cot T) y = (2a)(sin^2 T) how? lol here's what i got y = (sin^2 T) y = (2a)y^2 y = 2a then? do the same for X? i'm stuck there

(x-1)^2 + y^2 = 36 Center(1,0) radius 6

how'd you get (4a²+x²) from x² = (4a²)(csc²(T)-1) ? i know you can x² = sin²(T) but how'd you get (4a²+x²)??