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kay bri
Questions (1)
The first three equations I have solved, I would just appreciate someone checking them over to make sure I'm doing them right.
Fi
4 answers
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Answers (1)
in the first one: 16x^2z ,40xz^2 , 72z^3 the only question I have is, how can it be 4xz when they don't all have the variable 'x'? the way I factored it was like this: 16x^2z 16 = 8 & 2 x^2z 4&2 (x)(x)(z) 2&2 = 2^4 40xz^2 40 = 10 & 4 xz^2 5&2 2&2 (x)(z)(z)
