joleen

If you throw a cricket ball up into the air and the ball leaves your hand at 1.8m and travel with a speed of 9.7m s. What is the speed at the point it hits the floor. Accerlation due to gravity is 9.8 ms no air resistance

How do i rearrange the equation to make d the subject. e = d/ab (d/ab has a square root sign over it)

A woman throws a cricket ball upwards into the air. The ball leaves the womans hand at 1.8m above the ground at speed of 9.7. It rises and then falls back to the ground. Considering the energies involved calculate the speed at the point it hits the ground...

how do i make d the subject? L=4pisignCd^

A non-metal element which lies in the third row of the Periodic Table forms a gaseous compound H2Y with hydrogen and the compound Li2Y with lithium, which has a solid crystalline structure and a high melting point (greater than 900 °C). • A non-metal elem...

Is that the same as Ek = ½mv² - ½mu² or does mgh have to be in the equation?