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jenny.t
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Ξ£πΉπ¦=πππ¦=0β(1.20Γ104ππ+π)π+ππ€ππ+1100π=0 Where π is the mass of the added water and π£ is the sphereβs volume. 1.20Γ104ππ+π=1.03Γ103[43π(1.50)3]+1100π9.8π/π 2=2.67Γ103ππ