jenny.t

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The following questions were asked by visitors named jenny.t.

Answers

The following answers were posted by visitors named jenny.t.

Σ𝐹𝑦=π‘šπ‘Žπ‘¦=0βˆ’(1.20Γ—104π‘˜π‘”+π‘š)𝑔+𝑝𝑀𝑔𝑉+1100𝑁=0 Where π‘š is the mass of the added water and 𝑣 is the sphere’s volume. 1.20Γ—104π‘˜π‘”+π‘š=1.03Γ—103[43πœ‹(1.50)3]+1100𝑁9.8π‘š/𝑠2=2.67Γ—103π‘˜π‘”
9 years ago