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jasmineT
Questions (6)
Consider the area between the graphs x+1y=12 and x+8=y2 . This area can be computed in two different ways using integrals
First
1 answer
1,814 views
Can someone look at my work and see what i did wrong. I did this 100 times but i keep getting it wrong
Sketch the region enclosed
2 answers
532 views
f(x)=[5x^3-4x^2-8x+9]/[2x^2-1x-3]
Find the equation of the non-vertical asymptote. y = Does f(x) intersect its non-vertical
1 answer
619 views
f(x)=[5x^3-4x^2-8x+9]/[2x^2-1x-3]
Find the equation of the non-vertical asymptote. y = Does f(x) intersect its non-vertical
1 answer
672 views
Use implicit differentiation to find the slope of the tangent line to the curve
y/x+6y=x^2–6 at the point (1,–5/31) . Again i
5 answers
602 views
Find the slope of the tangent line to the curve (a lemniscate)
2(x^2+y^2)^2=25(x^2–y^2) at the point (–3,1) . I know that we
4 answers
842 views
Answers (3)
Thank you soooo much steve i finally got it right!!!! :D
Oh my goodness, thank you soooo much for writing it out i totally wasn't getting it! THank you so much :) Do you think you coul check my arithmatic for another problem? It's Use implicit differentiation to find the slope of the tangent line to the curve
I got y'=(2x+x^2+12yx+6y^2-y)/(x+6y+6) But when i plugged in the numbers it came out right... do you think the equation is wrong or i just typed in the numbers wrong? BTW thanks for replying!