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jahil
Questions (9)
A 2.50- object is moving along the axis at 1.60 . As it passes the origin, two forces and are applied, both in the direction
0 answers
573 views
Vector V(with an arrow at the top) represents a displacement of 120. at 29.0 counterclockwise from the x axis. Write unit in
1 answer
521 views
Water is discharged from a pipeline at a velocity v(in ft/sec) given by v=1240p^(1/2), where p is the pressure (in psi). I f the
2 answers
5,125 views
Help please help me understand what i am doing wrong in this problem! x^3+3x^2y+y^3=8 find dy/dx using implict differentiation.
1 answer
513 views
If a doctor tells you to drink 1 liter of water per day, answer the following questions(assuming the density of water to be
4 answers
792 views
For a certain first-order reaction the rate constan is 2.9 s-1. what is the fraction of the reactant remaining after 4 half
3 answers
474 views
what is the approximate pH of a solution labeled 0.050 M HClO? I realized my mistake on my last post but this isnt a strong acid
3 answers
4,650 views
What is the approximate pH of a solution labeled 6 x 10^-5 M HBr?
5 answers
6,654 views
What is thhe pH of 500mL of solution containing 0.0124 grams of Ca(OH)2?
2 answers
5,454 views
Answers (7)
Thank you so much Reiny you rock! I was putting that .406 in for V but i did have 620 with the 33.0^-1/2. Thanks you Rock!!!!!
So if i were asked for grams of Hydrogen per day? it would be 1 mole H20 X 2 grams of H/1 mole H20
I think so could you critique this? 1. I came up with 1000grams of H20 2. 1 mole H20 X 6.022X10^23/1 mole H20=6.0222X10^23 Molecules Oxygen 3. 1 mole H20 x 1 atom of oxygen/1 mole H20= 1 atom of Oxygen Is this correct I really am trying to learn and
thanks so in any other question i can still use to as my base number raised to whatever half life is provided?
i still don't get it. (H+)=x/0.050M
0.0124/121.64= 1.02 x 10^-4g/mol 1.02 x 10^-4/ .5= 2.04 x 10^-4 2.04 x 10^-4*2=4.08x 10^-4 -log(4.08 x 10^-4)= 3.39 14-3.39=10.61 thank you so much!!!!!!
4.2 thank you so much do u have time for another one?
