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Find starting # of moles of acid & base (2L)(1M) = 2 moles HA (.5L)(1M)= .5 moles A Add 8 g NaOH Convert grams to mole 8g (1mol/40g) = .2 moles NaOH Find resulting # of moles 2 mol - .2 mol = 1.8 mol HA .5 mol + .2 mol = .7 mol A Use
