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Questions and answers by
igweka Emmanuel
Answers (1)
Sn = n/2(2a+ (n-1)d )=168 S12 = 12/2( 2a + (12-1)d )=168 => 6(2+11d)=168 => 12a+ 66d = 168 ...................equ (1) Tn =a + (n-1)d T3= a + (3-1)d ..............equ(2) Then Work equ(1) and 2 12a +66d=168 a + 2d = 7 a = 7-2d Substitute "a" 12(7-2d) + 66d =
