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hotibolshe
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1. Find mol of NaOH: NaOH: 44.3mL * 0.128 mol / 1 L -> 5,6704 * 10⁻³ mol NaOH Since proportion NaOH and HCl is 1:1, 5,67 * 10⁻³ mol HCl left, after previous NH₃ + HCl reaction. 2. Find initial mol of HCl HCl: 46.3 mL * 0.213 mol / 1 L -> 9,86 *
