herjaz

when water is added to solid calcium carbide, CaC2, acetylene gas, C2H2, and calcium hydroxide, Ca(OH)2 are produced. how do i write a balanced equation for the reaction.

when water is added to solid calcium carbide, CaC2, acetylene gas, C2H2, and calcium hydroxide, Ca(OH)2 are produced. how many moles of acetylene are produced when 0.50 mole of calcium carbide reacts? can anyone explain this to me please

when water is added to solid calcium carbide, CaC2, acetylene gas, C2H2, and calcium hydroxide, Ca(OH)2 are produced. how many moles of calcium carbide are needed to completely react with 5.00 * 10^22 water molecules? can someone explain the steps

we started off with this equation below CaC2 + C2H2 --> Ca(OH)2 (right?) then as per DrBob222 its balanced below, CaC2 + 2H2O ==> C2H2 +Ca(OH)2 ok this is how I start by trying to balance this equation. on the reactant side there's 4C, 1Ca, and 2H and on...